(w^2+11w+28)/(5w^2-80)

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Solution for (w^2+11w+28)/(5w^2-80) equation: 


D( w )

5*w^2-80 = 0

5*w^2-80 = 0

5*w^2-80 = 0

5*w^2 = 80 // : 5

w^2 = 16

w^2 = 16 // ^ 1/2

abs(w) = 4

w = 4 or w = -4

w in (-oo:-4) U (-4:4) U (4:+oo)

(w^2+11*w+28)/(5*w^2-80) = 0

w^2+11*w+28 = 0

w^2+11*w+28 = 0

DELTA = 11^2-(1*4*28)

DELTA = 9

DELTA > 0

w = (9^(1/2)-11)/(1*2) or w = (-9^(1/2)-11)/(1*2)

w = -4 or w = -7

(w+7)*(w+4) = 0

((w+7)*(w+4))/(5*w^2-80) = 0

( w+4 )

w+4 = 0 // - 4

w = -4

( w+7 )

w+7 = 0 // - 7

w = -7

w in { -4} 

w = -7

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